Sodium Fluoride → Pyrimidine, tetrafluoro-
Reaction equation
[F:1]F.[F:3][C:4]1[N:9]=[C:8]([F:10])[CH:7]=[C:6]([F:11])[N:5]=1.[F-].[Na+]>ClC(Cl)(Cl)F>[F:10][C:8]1[N:9]=[C:4]([F:3])[N:5]=[C:6]([F:11])[C:7]=1[F:1]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
0.5 mol of fluorine in the form of a 30% by volume mixture with helium was introduced into a suspension of 29.0 g (0.216 mol) of 2,4,6-trifluoropyrimidine, 21 g of sodium fluoride (0.5 mol) and 250 ml of trichlorofluoromethane at a temperature of -78° C. The rate of introduction was 0.15 mol of fluorine per hour. After the introduction was complete, the reaction mixture was filtered and 21.0 g of tetrafluoropyrimidine (=64% of theory) were obtained from the filtrate by distillation.
Workup
- filtrationthe reaction mixture was filtered
Sources & evidence
- ORD record
- ord-b1974ed2dd484943bc45cbd3d3c45657
- Source dataset
- uspto-grants-1992_09
- Patent number
- US05145961
Reaction notes
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