Sodium Iodide → HCID 67119908, compound

Participants

Reaction Steps

Anhydrous cerium chloride (0.99 g, 4.0 mmol) and sodium iodide (1.8 g, 12.0 mmol) are added to 10 ml of anhydrous tetrahydrofuran as a solvent to form a suspension. Dissolving 1.07 g (4.0 mmol) of 2-bromo-1-(4-morpholinophenyl)ethanone and 0.76 g (4.0 mmol) of N-benzyl-4-piperidone into 10 ml of anhydrous tetrahydrofuran, and the solution is added dropwise to the above suspension and reacting at room temperature for 2 hours. Operating according to the post-treatment procedure in General Method three to obtain 0.69 g of a white crystal, with yield of 34.3%.

Provenance & Evidence