HRID1898592

反应详情

EQUATION

反应方程式

REACTANTS

反应物

结构：CCC[CH2][Sn]([CH2]CCC)([CH2]CCC)[c]1ccccn1

HCID607784

2-(Tributylstannyl)pyridine

C17H31NSn

结构：CCC[CH2][Sn]([CH2]CCC)([CH2]CCC)[c]1cc(C(C)(C)C)ccn1

HCID57516631

未命名化合物

结构：CC(C)(C)[C@@H](NC(=O)c1cn(COCC[Si](C)(C)C)c2ncc(Br)nc12)C(=O)N1CCC(C#N)CC1

HCID58438532

未命名化合物

结构：C[Si](C)(C)CCOCn1cc(C(=O)N[C@@H](C(=O)N2CCC(C#N)CC2)C2CC2)c2nc(Br)cnc21

HCID86657873

未命名化合物

PRODUCTS

生成物

结构：CC(C)(C)[C@@H](NC(=O)c1c[nH]c2ncc(-c3ccccn3)nc12)C(=O)N1CCC(C#N)CC1

HCID58438566

未命名化合物

PROCEDURE

实验过程

Prepared according to the procedure outlined in Example 111, steps 4-5 substituting 2-bromo-5-(2-trimethylsilanyl-ethoxymethyl)-5H-pyrrolo[2,3-b]pyrazine-7-carboxylic acid [(R)-1-(4-cyano-piperidine-1-carbonyl)-2,2-dimethyl-propyl]-amide for 2-bromo-5-(2-trimethylsilanyl-ethoxymethyl)-5H-pyrrolo[2,3-b]pyrazine-7-carboxylic acid [(R)-2-(4-cyano-piperidin-1-yl)-1-cyclopropyl-2-oxo-ethyl]-amide and 2-(tributylstannanyl)pyridine for 4-tert-butyl-2-(tributylstannyl)pyridine. MS: (M+H)+=446.

WORKUP

后处理

customPrepared

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-49c9a0e7e7884c6db7ec02dfbf3a6a5a
来源数据集: uspto-grants-2013_08
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08518945B2
来源说明: uspto-grants-2013_08

反应 SMILES

[C:1]([CH:3]1[CH2:8][CH2:7][N:6]([C:9]([C@H:11]([NH:16][C:17]([C:19]2[C:27]3[C:22](=[N:23][CH:24]=[C:25](Br)[N:26]=3)[N:21](COCC[Si](C)(C)C)[CH:20]=2)=[O:18])[C:12]([CH3:15])([CH3:14])[CH3:13])=[O:10])[CH2:5][CH2:4]1)#[N:2].C([CH:39]1[CH2:44][CH2:43][N:42](C(=O)[C@H](NC(C2C3C(=NC=C(Br)N=3)N(COCC[Si](C)(C)C)C=2)=O)C2CC2)[CH2:41][CH2:40]1)#N.C([Sn](CCCC)(CCCC)C1C=CC=CN=1)CCC.C(C1C=CN=C([Sn](CCCC)(CCCC)CCCC)C=1)(C)(C)C>>[C:1]([CH:3]1[CH2:8][CH2:7][N:6]([C:9]([C@H:11]([NH:16][C:17]([C:19]2[C:27]3[C:22](=[N:23][CH:24]=[C:25]([C:41]4[CH:40]=[CH:39][CH:44]=[CH:43][N:42]=4)[N:26]=3)[NH:21][CH:20]=2)=[O:18])[C:12]([CH3:14])([CH3:13])[CH3:15])=[O:10])[CH2:5][CH2:4]1)#[N:2]