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HRID1904247

反应详情

EQUATION

反应方程式

HRID 1904247 的结构方程式

REACTANTS

反应物

2
结构：CC(C)(C)n1ncc(Cl)c(Cl)c1=O
HCID2782225

2-tert-Butyl-4,5-dichloropyridazin-3(2H)-one

C8H10Cl2N2O

结构：CCN(CC)CCOc1ccc(C(C)O)cc1
HCID14671819

未命名化合物

PRODUCTS

生成物

1
结构：CCN(CC)CCOc1ccc(C(C)Oc2cnn(C(C)(C)C)c(=O)c2Cl)cc1
HCID14671820

未命名化合物

收率 37.2%

PROCEDURE

实验过程

By using 1.0 g of 2-t-butyl-4,5-dichloro-3(2H)-pyridazinone and 1.1 g of 4-(2-diethylaminoethoxy)-α-methylbenzyl alcohol and similarly to the procedures in Preparation Example 1, a crude product was obtained. The crude product was then purified through column chromatography (eluting with chloroform/methanol=200/5) to obtain 710 mg of the aimed product as an oil.

WORKUP

后处理

  1. customsimilarly to the procedures in Preparation Example 1
  2. customa crude product was obtained
  3. customThe crude product was then purified through column chromatography (eluting with chloroform/methanol=200/5)