2-(4-Methylphenyl)ethoxyacetic acid → 2-[2-(4-Methylphenyl)ethoxy]ethanol

HRID 1905969Notes

Reaction equation

HRID 1905969 reaction equation
[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][CH2:9][O:10][CH2:11][C:12](O)=[O:13])=[CH:4][CH:3]=1.[H-].[Al+3].[Li+].[H-].[H-].[H-]>>[CH3:1][C:2]1[CH:3]=[CH:4][C:5]([CH2:8][CH2:9][O:10][CH2:11][CH2:12][OH:13])=[CH:6][CH:7]=1

Participants

3

Reactant 2

HCID 132089242-(4-Methylphenyl)ethoxyacetic acidHCID 21226445Aluminium lithium hydride

Product 1

HCID 132089312-[2-(4-Methylphenyl)ethoxy]ethanolYield 88%

Procedure

The 2-(4-methylphenyl)ethoxyacetic acid obtained according to the preceding paragraph was reduced with lithium aluminum hydride in a manner analogous to that described in Example 1(b) to give 6.6 g (88%) of 2-[2-(4-methylphenyl)ethoxy]ethanol in the form of an oil which was homogeneous according to chromatography.

Sources & evidence

ORD record
ord-a92922499a7c40edb70a961b4848b83e
Source dataset
uspto-grants-1987_03
Patent number
US04649160

Reaction notes

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