2-(4-Methylthiophenyl)ethoxyacetic acid → 2-[2-(4-Methylthiophenyl)ethoxy]ethanol
Reaction equation
[CH3:1][S:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][O:11][CH2:12][C:13](O)=[O:14])=[CH:5][CH:4]=1.[H-].[Al+3].[Li+].[H-].[H-].[H-]>>[CH3:1][S:2][C:3]1[CH:4]=[CH:5][C:6]([CH2:9][CH2:10][O:11][CH2:12][CH2:13][OH:14])=[CH:7][CH:8]=1Participants
3
Procedure
The 2-(4-methylthiophenyl)ethoxyacetic acid obtained according to the preceding paragraph was reduced with lithium aluminum hydride in a manner analogous to that described in Example 1(b) to give 1.97 g (54%) of 2-[2-(4-methylthiophenyl)ethoxy]ethanol in the form of an oil which was homogeneous according to chromatography.
Sources & evidence
- ORD record
- ord-98a46806ad934b769e16d501d57f4844
- Source dataset
- uspto-grants-1987_03
- Patent number
- US04649160
Reaction notes
Loading…