HRID1907750

反应详情

EQUATION

反应方程式

HRID 1907750 的结构方程式

PROCEDURE

实验过程

Following the same procedure as described in Example 1, steps 6 and 7 (scheme 1), using compound 4 but substituting compounds 7 & 8 for compounds 281 & 282, the title compound 283 was obtained (step 2: 31% yield, step 3: 23% yield).