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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1910365Generated: October 31, 2026

Triethylamine → 2-Bromoethyl methacrylate

https://huagongshe.com/reaction/1910365

Reaction equation

Participants

RoleNameHCIDCharge
ReactantTriethylamineHCID 8471—
Reactant2-BromoethanolHCID 10898—
ReactantMethacryloyl chlorideHCID 13528—
SolventTetrahydrofuranHCID 8028—
Product2-Bromoethyl methacrylateHCID 7827190%

Reaction Steps

A reactor was charged with 12.50 g (100 mmol) of 2-bromoethanol and 100 ml of tetrahydrofuran (THF) at 0° C. in a nitrogen atmosphere. After the dropwise addition of 10.45 g (100 mmol) of methacrylic chloride and 11.13 g (110 mmol) of triethylamine, the mixture was reacted at 25° C. for 30 minutes with stirring. After completion of the reaction, the reaction mixture was concentrated under reduced pressure, and the residue was purified by distillation to obtain 17.30 g of 2-bromoethyl methacrylate shown by the following formula (M-20′) (yield: 90%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08603726B2
Source datasetuspto-grants-2013_12
ORD IDord-2561f964dd4c4698b135838715896a17
Source noteuspto-grants-2013_12