HRID1944956

反应详情

EQUATION

反应方程式

REACTANTS

反应物

结构：COc1cccc(Nc2c(C(N)=O)cnc3c(C)cc(S(=O)(=O)c4cccc(C(=O)Nc5ccc(CCNC[C@H](O)c6ccc(OCc7ccccc7)c7[nH]c(=O)ccc67)cc5)c4)cc23)c1

HCID86659111

未命名化合物

结构：COc1cccc(Nc2c(C(N)=O)cnc3c(C)cc(S(=O)(=O)c4cccc(CN(C)C(=O)c5cccc(CC(C)(C)NC[C@H](O[Si](C)(C)C(C)(C)C)c6ccc(OCc7ccccc7)c7[nH]c(=O)ccc67)c5)c4)cc23)c1

HCID86659115

未命名化合物

PRODUCTS

生成物

结构：COc1cccc(Nc2c(C(N)=O)cnc3c(C)cc(S(=O)(=O)c4cccc(CN(C)C(=O)c5cccc(CC(C)(C)NC[C@H](O)c6ccc(OCc7ccccc7)c7[nH]c(=O)ccc67)c5)c4)cc23)c1

HCID86659114

未命名化合物

PROCEDURE

实验过程

The title compound was synthesized in a manner analogous to that described for Intermediate 144, using Intermediate 143 as a substrate. ES/MS calcd. for C55H54N6NaO8S+ 981.4. Found m/z=981.4 (M+Na)+.

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-d2fd0472e9a04e13a318d1274fb21643
来源数据集: uspto-grants-2013_03
DOI: 10.6084/m9.figshare.5104873.v1
专利: US08394829B2
来源说明: uspto-grants-2013_03

反应 SMILES

C(OC1C=CC([C@@H](O)CNCCC2C=CC(NC(C3C=C(S(C4C=C5C(=C(C)C=4)N=CC(C(N)=O)=C5NC4C=CC=C(OC)C=4)(=O)=O)C=CC=3)=O)=CC=2)=C2C=1NC(=O)C=C2)C1C=CC=CC=1.[CH2:67]([O:74][C:75]1[CH:76]=[CH:77][C:78]([C@@H:86]([O:136][Si](C(C)(C)C)(C)C)[CH2:87][NH:88][C:89]([CH3:135])([CH3:134])[CH2:90][C:91]2[CH:92]=[C:93]([CH:131]=[CH:132][CH:133]=2)[C:94]([N:96]([CH2:98][C:99]2[CH:100]=[C:101]([S:105]([C:108]3[CH:109]=[C:110]4[C:115](=[C:116]([CH3:118])[CH:117]=3)[N:114]=[CH:113][C:112]([C:119]([NH2:121])=[O:120])=[C:111]4[NH:122][C:123]3[CH:128]=[CH:127][CH:126]=[C:125]([O:129][CH3:130])[CH:124]=3)(=[O:107])=[O:106])[CH:102]=[CH:103][CH:104]=2)[CH3:97])=[O:95])=[C:79]2[C:84]=1[NH:83][C:82](=[O:85])[CH:81]=[CH:80]2)[C:68]1[CH:73]=[CH:72][CH:71]=[CH:70][CH:69]=1>>[CH2:67]([O:74][C:75]1[CH:76]=[CH:77][C:78]([C@@H:86]([OH:136])[CH2:87][NH:88][C:89]([CH3:134])([CH3:135])[CH2:90][C:91]2[CH:92]=[C:93]([CH:131]=[CH:132][CH:133]=2)[C:94]([N:96]([CH2:98][C:99]2[CH:100]=[C:101]([S:105]([C:108]3[CH:109]=[C:110]4[C:115](=[C:116]([CH3:118])[CH:117]=3)[N:114]=[CH:113][C:112]([C:119]([NH2:121])=[O:120])=[C:111]4[NH:122][C:123]3[CH:128]=[CH:127][CH:126]=[C:125]([O:129][CH3:130])[CH:124]=3)(=[O:107])=[O:106])[CH:102]=[CH:103][CH:104]=2)[CH3:97])=[O:95])=[C:79]2[C:84]=1[NH:83][C:82](=[O:85])[CH:81]=[CH:80]2)[C:68]1[CH:69]=[CH:70][CH:71]=[CH:72][CH:73]=1