HRID1951410

反应详情

EQUATION

反应方程式

HRID 1951410 的结构方程式

PROCEDURE

实验过程

The title compound is prepared in analogy to example 10 from 50 mg (0.13 mmol) of 3-acetyl-2-methyl-4-(2-methyl-4-oxo-4H-chromen-8-yl)-4,6-dihydro-1,6-naphthyridin-5(1H)-one and 24 mg (0.15 mmol) of butanesulfonyl chloride. 48 mg (72% of theory) of the product are obtained as a pale yellow solid.

WORKUP

后处理

  1. custom48 mg (72% of theory) of the product are obtained as a pale yellow solid