HRID196107

反应详情

EQUATION

反应方程式

HRID 196107 的结构方程式

REACTANTS

反应物

3

结构：CC1CNCC(C)N1

Piperazine, 2,6-dimethyl-

C6H14N2

结构：C1CN2CCC1CN2

1,2-Diazabicyclo(2.2.2)octane

C6H12N2

结构：O=C(O)c1cn(C2CC2)c2cc(Cl)c(F)cc2c1=O

Fluoroquinolonic acid

C13H9ClFNO3

PRODUCTS

生成物

1

结构：CC1CN(c2cc3c(cc2F)c(=O)c(C(=O)O)cn3C2CC2)CC(C)N1

1-Cyclopropyl-7-(3,5-dimethylpiperazin-1-yl)-6-fluoro-4-oxo-1,4-dihydroquinoline-3-carboxylic acid

C19H22FN3O3