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HRID 1962832作成日:2026年10月25日

Methyl 4-amino-o-anisate → Methyl 4-amino-5-bromo-2-methoxybenzoate

https://huagongshe.com/reaction/1962832

反応式

関与物質

役割名称HCID仕込み量
反応物Methyl 4-amino-o-anisateHCID 168705—
反応物1H-indole-2-carbohydrazideHCID 231954—
反応物N-BromosuccinamideHCID 9834204—
溶媒EthanolHCID 702—
生成物Methyl 4-amino-5-bromo-2-methoxybenzoateHCID 2768028—

反応手順

An indole hydrazide can also be prepared by treating a solution of 2-methoxy-4-amino-benzoic acid methyl ester (xvii) in ethanol with N-bromosuccinamide to form 2-methoxy-4-amino-5-bromo-benzoic acid methyl ester (xviii) (see Scheme VIII). A solution of 2-methoxy-4-amino-5-bromo-benzoic acid methyl ester (xviii) in DMF is then reacted with trimethyl-prop-1-ynyl silane (xix) in the presence of with palladium acetate, Na2CO3, triphenylphosphine and tetrabutylaminium iodide to form 6-methoxy-3-methyl-2-trimethylsilanyl-1H-indole-5-carboxylic acid methyl ester (xx). Compound (xx) is then treated with an aqueous HCl solution to remove the trimethylsilanyl group and form 6-methoxy-3-methyl-1H-indole-5-carboxylic acid methyl ester (xxi). Compound (xxi) is treated with NaOH in a THF/H2O solution to convert the ester to a carboxylic acid. The carboxylic acid is then activated by treating it with oxalyl chloride in dichloromethane and a catalytic amount of DMF, then the activated carboxylic acid is converted to a hydrazide by treating it with hydrazine hydrate in dichloromethane to form 6-methoxy-3-methyl-1H-indole-5-carboxylic acid hydrazide (xxii). Hydrazide (xxii) can be used in the method of Scheme V or VI to form a compound of the invention

情報源と証拠

DOI10.6084/m9.figshare.5104873.v1
特許番号US08415377B2
出典データセットuspto-grants-2013_04
ORD IDord-cb29bdd2cb8b40568db5e76e434dc9e9
出典メモuspto-grants-2013_04