HRID1966623

反应详情

EQUATION

反应方程式

HRID 1966623 的结构方程式

PROCEDURE

实验过程

Obtained from Intermediate 14 (0.41 g, 1.56 mmol) by the procedure described for the Intermediate 13. Purification by column chromatography with silica gel and methylene chloride/acetone (20:1) as eluent gave the title compound (0.38 g, 88%) as oil.

WORKUP

后处理

  1. customPurification by column chromatography with silica gel and methylene chloride/acetone (20:1) as eluent