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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1967004Generated: October 31, 2026

Methyl iodide → HCID 67320191, compound

https://huagongshe.com/reaction/1967004

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl iodideHCID 6328—
ReactantSodium hydrideHCID 24758—
ReactantSodium BicarbonateHCID 516892—
ReactantHCID 15751484HCID 15751484—
SolventDimethylformamideHCID 6228—
SolventEthyl AcetateHCID 8857—
ProductHCID 67320191HCID 6732019182%

Reaction Steps

To a solution of 500 mg (2.17 mmol) (5-chloro-4-fluoro-2-nitro-phenyl)-cyclopropyl-amine (J. Med. Chem. 1992, 35(8), 1385) in 5 mL N,N-dimethylformamide was added 104 mg (2.385 mmol) sodium hydride (60% dispersion in mineral oil) and 339 mg (2.385 mmol) methyl iodide. The reaction mixture was stirred for 6 hours at room temperature and then poured on 30 mL 10% aqueous sodium bicarbonate solution and 30 mL ethyl acetate. The layers were separated and the aqueous layer was extracted a second time with 30 mL ethyl acetate. The organic layers were washed with 30 mL brine, dried over magnesium sulfate, filtered and concentrated under vacuum. The residue was purified by silica gel chromatography using a MPLC system (CombiFlash Companion, Isco Inc.) eluting with a gradient of n-heptane:ethyl acetate 100:0 to 80:20) to give 433 mg (82%) of the desired compound as a yellow oil. MS (ESI): m/z=245.049 [M+H]+.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08420647B2
Source datasetuspto-grants-2013_04
ORD IDord-dd6ecef3468e4b4ea70ea51e351ebd80
Source noteuspto-grants-2013_04