Sodium Hydroxide → 4-(2-Methyl-1H-indol-3-yl)butanoic acid

Participants

Reaction Conditions

Reaction Steps

To a solution of methyl 4-(2-methylindol-3-yl)-butyrate (1.65 g) in methanol (50 ml) was added 1N aqueous sodium hydroxide (18 ml) at 20° C. and the mixture was stirred at 20° C. for 3 hours. After evaporation of the solvent, the residue was poured into a mixture of ethyl acetate and 1N hydrochloric acid. The organic layer was separated, washed with water and brine, and dried over magnesium sulfate. After evaporation of solvent, the crystalline residue was washed with hexane to give 4(2-methylindol-3-yl)butyric acid (1.23 g) as reddish brown crystals.

Provenance & Evidence