Tetralin → 1-Naphthyl hexanoate
Reaction equation
[C:1]([OH:8])(=[O:7])[CH2:2][CH2:3][CH2:4][CH2:5][CH3:6].[CH2:9]1[C:18]2[C:13](=[CH:14][CH:15]=[CH:16][CH:17]=2)[CH2:12][CH2:11][CH2:10]1>>[C:1]([O:8][C:17]1[C:18]2[C:13](=[CH:12][CH:11]=[CH:10][CH:9]=2)[CH:14]=[CH:15][CH:16]=1)(=[O:7])[CH2:2][CH2:3][CH2:4][CH2:5][CH3:6]Participants
3
Reactant 2
Product 1
Procedure
The procedure of Example 2 was followed except that hexanoic acid (33 g.; 284 m mols) was used in place of octanoic acid and the reaction time was 31/2 hours. Analysis showed that about 55% of the tetralin was converted producing naphthyl hexanoate in 62% selectivity.
Workup
- custom2 hours
Sources & evidence
- ORD record
- ord-248074c31ded446cae33124f520ce424
- Source dataset
- uspto-grants-1985_04
- Patent number
- US04512927
Reaction notes
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