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HRID2038368

反应详情

EQUATION

反应方程式

HRID 2038368 的结构方程式

REACTANTS

反应物

2
结构：CCOC(=O)c1nc(-c2cccc(Cl)c2)c(Br)s1
HCID70801641

未命名化合物

结构：O=C(O)c1nc(-c2ccc(F)c(Cl)c2)c(-c2cc(F)cc(Cl)c2)s1
HCID70801644

未命名化合物

PRODUCTS

生成物

1
结构：O=C(O)c1nc(-c2cccc(Cl)c2)c(-c2cc(F)cc(Cl)c2)s1
HCID70801640

未命名化合物

PROCEDURE

实验过程

The preparation of the title compound takes place in analogy to the synthesis of the compound from Example 8A starting with the compound from Example 5A. 83.0 mg (78% of theory) of the title compound are obtained.