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HRID2038388

反应详情

EQUATION

反应方程式

HRID 2038388 的结构方程式

REACTANTS

反应物

2
结构：O=C1CN(C(=O)c2nc(-c3ccc(F)c(Cl)c3)c(-c3cc(F)cc(Cl)c3)s2)CN1
HCID50942848

未命名化合物

结构：O=C(O)c1nc(-c2cccc(Cl)c2)c(-c2cc(F)cc(Cl)c2)s1
HCID70801640

未命名化合物

PRODUCTS

生成物

1
结构：O=C1CN(C(=O)c2nc(-c3cccc(Cl)c3)c(-c3cc(F)cc(Cl)c3)s2)CN1
HCID50942914

未命名化合物

PROCEDURE

实验过程

The preparation of the title compound takes place in analogy to the synthesis of the compound from Example 1 starting with the compound from Example 10A. 40.0 mg (41% of theory) of the title compound are obtained.