Sodium Azide → HCID 20344722, compound

HRID 2049183Notes

Reaction equation

HRID 2049183 reaction equation
[N:1](C1C=CC=C2C(N(CCCCN3C(=O)C4=C(N=[N+]=[N-])C=CC=C4C3=O)C(=O)C=12)=O)=[N+:2]=[N-].[N+:33]([C:36]1[CH:72]=[CH:71][CH:70]=[C:38]2[C:39]([N:41]([CH:44]([CH3:69])[CH2:45][CH2:46][CH2:47][CH2:48][CH2:49][CH2:50][CH2:51][CH2:52][CH:53]([N:55]3[C:59](=[O:60])[C:58]4=[C:61]([N+:65]([O-])=O)[CH:62]=[CH:63][CH:64]=[C:57]4[C:56]3=[O:68])[CH3:54])[C:42](=[O:43])[C:37]=12)=[O:40])([O-])=O.[N-:73]=[N+:74]=[N-].[Na+]>>[N:33]([C:36]1[CH:72]=[CH:71][CH:70]=[C:38]2[C:39]([N:41]([CH:44]([CH3:69])[CH2:45][CH2:46][CH2:47][CH2:48][CH2:49][CH2:50][CH2:51][CH2:52][CH:53]([N:55]3[C:59](=[O:60])[C:58]4=[C:61]([N:65]=[N+:73]=[N-:74])[CH:62]=[CH:63][CH:64]=[C:57]4[C:56]3=[O:68])[CH3:54])[C:42](=[O:43])[C:37]=12)=[O:40])=[N+:1]=[N-:2]

Participants

4

Reactant 3

HCID 33557Sodium AzideHCID 20344715HCID 20344715, compoundHCID 20344716HCID 20344716, compound

Product 1

HCID 20344722HCID 20344722, compoundYield 80%

Procedure

The method of preparation is analogous to that described under (a), 8 g (0.014 mol) of 1,10-bis-(3-nitrophthalimidyl)-1,10-dimethyldecane and 2.36 g (0.035 mol) of sodium azide being used. Yield: 80% of theory. The reaction product is obtained in the form of a viscous oil.

Workup

  1. customThe method of preparation
  2. customThe reaction product is obtained in the form of a viscous oil

Sources & evidence

ORD record
ord-7087050ea960451ca9da862760201019
Source dataset
uspto-grants-1980_04
Patent number
US04197133

Reaction notes

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