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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2052750Generated: October 31, 2026

Iodoethane → N-Ethylphenothiazine

https://huagongshe.com/reaction/2052750

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
ReactantPhenothiazineHCID 7108—
ReactantPotassium HydroxideHCID 14797—
CatalystTetrabutylammonium hydrogen sulfateHCID 94433—
SolventTolueneHCID 1140—
ProductN-EthylphenothiazineHCID 219178—

Reaction Steps

A mixture of 10 g (0.05 mol) of phenothiazine (obtained from Fluka), 11.7 g (0.075 mol) of iodoethane (obtained from Aldrich), 4.2 g (0.075 mol) of potassium hydroxide, and 0.25 g of tetra-n-butylammonium hydrogen sulfate (obtained from Aldrich) in 200 ml of dry toluene was refluxed for 24 hours. After cooling, the reaction mixture was filtered, and the solvent was evaporated. The product was crystallized from methanol. The yield of 10-ethylphenothiazine was 10.2 g (90%). The melting point of the product was 103-104° C. The 1H-NMR spectrum (100 MHz) of the product in CDCl3 was characterized by the following chemical shifts (δ, ppm): 1.40 (t, J=7.0 Hz, 3H, CH3); 3.90 (q, J=7.0 Hz, 2H, CH2); 6.78-7.32 (m, 8H, Ar).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07326506B2
Source datasetuspto-grants-2008_02
ORD IDord-7d2196d0a09441f3bd870125976e9caa
Source noteuspto-grants-2008_02