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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2083450Generated: October 31, 2026

Aluminum(III) Chloride → 2-Ethyl-2-n-propyl-5-hydroxy-6,7-dichloro-1-indanone

https://huagongshe.com/reaction/2083450

Reaction equation

Participants

RoleNameHCIDCharge
ReactantAluminum(III) ChlorideHCID 6451240—
Reactant2-Ethyl-2-n-propyl-5-methoxy-6,7-dichloro-1-indanoneHCID 12395563—
SolventHeptaneHCID 8900—
Product2-Ethyl-2-n-propyl-5-hydroxy-6,7-dichloro-1-indanoneHCID 12395585—

Reaction Steps

2-Ethyl-2-n-propyl-5-hydroxy-6,7-dichloro-1-indanone is prepared following substantially the same procedure described in Example 5, Step F, using the following substances: 2-ethyl-2-n-propyl-5-methoxy-6,7-dichloro-1-indanone (11 g., .037 mole), aluminum chloride (12.5 g., 0.094 mole) and heptane (400 ml.). The above procedure gives 9.0 g. of 2-ethyl-2-n-propyl-5-hydroxy-6,7-dichloro-1-indanone which after recrystallization from methylcyclohexane melts at 153° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04085219
Source datasetuspto-grants-1978_04
ORD IDord-28c1086691214403b992f4ac7a8c6258
Source noteuspto-grants-1978_04