Fmoc-N-Me-Val-N-Me-Tyr(Bzl)-NH2 → N-Me-Val-N-Me-Tyr-NH2

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Reaction Steps

Fmoc-N-Me-Val-N-Me-Tyr(Bzl)-NH2(802 mg, 1.29 mmol) was dissolved in a mixed solution of MeOH (6 ml) and ethyl acetate (6 ml), mixed with 20% palladium hydroxide-carbon (150 mg), followed by stirring in a hydrogen atmosphere at room temperature for 2 days. The mixture was filtered and the filtrate was concentrated under reduced pressure; the thus obtained residue was subjected to silica gel column chromatography (developing solvent: chloroform:methanol 10:1) to give the titled compound (216 mg, 55%).

Provenance & Evidence