1-(4-Fluorophenoxy)-3-nitrobenzene → 3-(4-Fluorophenoxy)aniline

HRID 2086495Notes

Reaction equation

HRID 2086495 reaction equation
[F:1][C:2]1[CH:17]=[CH:16][C:5]([O:6][C:7]2[CH:8]=[C:9]([N+:13]([O-])=O)[CH:10]=[CH:11][CH:12]=2)=[CH:4][CH:3]=1>C(O)C.[Pd]>[F:1][C:2]1[CH:17]=[CH:16][C:5]([O:6][C:7]2[CH:8]=[C:9]([CH:10]=[CH:11][CH:12]=2)[NH2:13])=[CH:4][CH:3]=1

Participants

4

Procedure

3-(4-fluorophenoxy)nitrobenzene (1.15 g, 4.93 mmol) from EX-634A was dissolved in ethanol (45 mL), and the solution was hydrogenated for 4 h in the presence of 5% palladium on charcoal. After the mixture was filtered through celite, the ethanol was removed in vacuo. The product was purified by flash column chromatography on silica gel eluting with ethyl acetate in hexane (1:10) to give 0.92 g (90%) of 3-(4-fluorophenoxy)aniline as a yellow oil, 99% pure by HPLC analysis. HRMS calcd. for C12H11FNO: 204.0824 [M+H]+, found: 204.0837.

Workup

  1. filtrationAfter the mixture was filtered through celite
  2. customthe ethanol was removed in vacuo
  3. customThe product was purified by flash column chromatography on silica gel eluting with ethyl acetate in hexane (1:10)

Sources & evidence

ORD record
ord-fffffe4d14804a56bd6d6f6d64d98144
Source dataset
uspto-grants-2004_04
Patent number
US06723753B2

Reaction notes

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