2-Fluoroethyl bromide → 1-(2-Fluoroethyl)-1,2,3,4-tetrahydro-7-quinolinol

Participants

Reaction Steps

500 mg (3.35 mmol) 1,2,3,4-Tetrahydro-quinolin-7-ol are dissolved in 8 mL DMF and stirred at 60° C. overnight with 0.325 mL (1.3 eq) 1-bromo-2-fluoroethane, in the presence of 0.63 mL (1.1 eq) diisopropylethylamine. The reaction mixture is extracted with 0.1 N aqu. HCl and ethyl acetate. The combined organic extracts are washed with brine, dried over sodium acetate and evaporated. The residue is column chromatographed (silica gel, ethyl acetate/petroleum ether 1:2 to 1:1) to yield 290 mg (44%) desired product as a brown oil.

Provenance & Evidence