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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2100723Generated: October 31, 2026

3-(4-Fluoro-3-methoxyphenyl)prop-2-enoic acid → 3-(4-Fluoro-3-methoxyphenyl)propanoic acid

https://huagongshe.com/reaction/2100723

Reaction equation

Participants

RoleNameHCIDCharge
Reactant3-(4-Fluoro-3-methoxyphenyl)prop-2-enoic acidHCID 53404313—
ReactantHCID 178418361HCID 178418361—
CatalystPalladiumHCID 23938—
SolventMethanolHCID 887—
SolventEthyl AcetateHCID 8857—
Product3-(4-Fluoro-3-methoxyphenyl)propanoic acidHCID 2109860699%

Reaction Steps

3-(4-Fluoro-3-methoxy-phenyl)-acrylic acid (6.2 g, 31.6 mmol) and Pd—C (10%, 620 mg) in ethyl acetate and methanol (1:1, 400 ml) was placed in a Parr apparatus. After the appropriate amount of hydrogen was taken up, the catalyst was filtered and the filtrate was concentrated in vacuo to give 6.2 g white solid (99% yield). LC-MS: m/e 197 (M−1)

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07572809B2
Source datasetuspto-grants-2009_08
ORD IDord-6f7d20897a1a4db185d7b0e41e78a833
Source noteuspto-grants-2009_08