HRID2104980

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID4311764

Sodium borohydride (Na(BH4))

H4BNa

结构：CCOc1cc(OC(C)C)c(F)c(C(Nc2ccc(-c3noc(C)n3)cc2)c2nc(-c3ccccc3C(C)=O)cn2C(c2ccccc2)(c2ccccc2)c2ccccc2)c1

HCID68812990

未命名化合物

PRODUCTS

生成物

HCID68812547

未命名化合物

收率 73.7%

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID887

Methanol

CH4O

PROCEDURE

实验过程

A solution of Intermediate 111.1 (40 mg, 0.05 mmol) and NaBH4 (5 mg) in 1 mL MeOH was stirred for 0.5 h at rt. The reaction mixture was partitioned between EtOAc and H2O, the organic layer was collected, dried (Na2SO4), filtered and concentrated to afford 30 mg of Intermediate 111.2. LCMS (2 min gradient) RT=1.49 min, 814.4 (M+H).

WORKUP

后处理

customThe reaction mixture was partitioned between EtOAc and H2O
customthe organic layer was collected
dry with materialdried (Na2SO4)
filtrationfiltered
concentrationconcentrated

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-c079cd8255874c1696fba433aa16bc12
来源数据集: uspto-grants-2009_08
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07576098B2
来源说明: uspto-grants-2009_08

反应 SMILES

[CH2:1]([O:3][C:4]1[CH:5]=[C:6]([O:58][CH:59]([CH3:61])[CH3:60])[C:7]([F:57])=[C:8]([CH:10]([NH:44][C:45]2[CH:50]=[CH:49][C:48]([C:51]3[N:55]=[C:54]([CH3:56])[O:53][N:52]=3)=[CH:47][CH:46]=2)[C:11]2[N:12]([C:25]([C:38]3[CH:43]=[CH:42][CH:41]=[CH:40][CH:39]=3)([C:32]3[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=3)[C:26]3[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=3)[CH:13]=[C:14]([C:16]3[CH:21]=[CH:20][CH:19]=[CH:18][C:17]=3[C:22](=[O:24])[CH3:23])[N:15]=2)[CH:9]=1)[CH3:2].[BH4-].[Na+]>CO>[CH2:1]([O:3][C:4]1[CH:5]=[C:6]([O:58][CH:59]([CH3:60])[CH3:61])[C:7]([F:57])=[C:8]([CH:10]([NH:44][C:45]2[CH:46]=[CH:47][C:48]([C:51]3[N:55]=[C:54]([CH3:56])[O:53][N:52]=3)=[CH:49][CH:50]=2)[C:11]2[N:12]([C:25]([C:32]3[CH:37]=[CH:36][CH:35]=[CH:34][CH:33]=3)([C:26]3[CH:31]=[CH:30][CH:29]=[CH:28][CH:27]=3)[C:38]3[CH:39]=[CH:40][CH:41]=[CH:42][CH:43]=3)[CH:13]=[C:14]([C:16]3[CH:21]=[CH:20][CH:19]=[CH:18][C:17]=3[CH:22]([OH:24])[CH3:23])[N:15]=2)[CH:9]=1)[CH3:2]