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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2114012Generated: October 30, 2026

Methyl iodide → 4-(2-Fluoro-4-nitrophenoxy)-6-methoxy-5-methylpyrrolo[2,1-f][1,2,4]triazine

https://huagongshe.com/reaction/2114012

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl iodideHCID 6328—
ReactantCesium carbonateHCID 10796—
Reactant4-(2-Fluoro-4-nitrophenoxy)-5-methylpyrrolo[2,1-f][1,2,4]triazin-6-olHCID 21081646—
SolventDimethylformamideHCID 6228—
Product4-(2-Fluoro-4-nitrophenoxy)-6-methoxy-5-methylpyrrolo[2,1-f][1,2,4]triazineHCID 2108165365%

Reaction Steps

To a solution of 4-(2-fluoro-4-nitrophenoxy)-5-methylpyrrolo[2,1-f][1,2,4]triazin-6-ol (52 mg, 0.17 mmol) in DMF (2 mL) was added Cs2CO3 (65 mg, 0.2 mmol) and the mixture was stirred at RT for 10 minutes. A solution of methyl iodide in DMF (0.2 mL, 0.2 mmol, 1 M) was added and the reaction solution was stirred at RT for 2 h. The reaction was quenched with EtOAc (5 mL) and H2O (5 mL). The organic layer was separated, dried with sodium sulfate and concentrated in vacuo to give the title compound (35 mg, 65%) as a yellow solid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07432373B2
Source datasetuspto-grants-2008_10
ORD IDord-a6261ef77c85445b9ddc953315bf5200
Source noteuspto-grants-2008_10