Perfluoropentacene → HCID 58854988, compound

HRID 2116895Notes

Reaction equation

HRID 2116895 reaction equation
[F:1][C:2]1[C:3]2[C:16]([C:17]([F:28])=[C:18]3[C:23]=1[C:22](F)=[C:21](F)[C:20](F)=[C:19]3F)=[C:15]([F:29])[C:14]1[C:5](=[C:6]([F:35])[C:7]3[C:12]([C:13]=1[F:30])=[C:11](F)[C:10](F)=[C:9](F)[C:8]=3F)[C:4]=2[F:36].FC1C2C(F)(F)C3C(F)(F)C4C(F)(F)C5C(=C(F)C(F)=C(F)C=5F)C(F)(F)C=4C(F)(F)C=3C(F)(F)C=2C(F)=C(F)C=1F>>[F:1][C:2]1[C:3]2[C:16](=[C:15]([F:29])[C:14]3[C:5]([C:4]=2[F:36])=[C:6]([F:35])[C:7]2[C:12](=[CH:11][CH:10]=[CH:9][CH:8]=2)[C:13]=3[F:30])[C:17]([F:28])=[C:18]2[C:23]=1[CH:22]=[CH:21][CH:20]=[CH:19]2

Participants

3

Reactant 2

HCID 12143313PerfluoropentaceneHCID 59815183HCID 59815183, compound

Product 1

HCID 58854988HCID 58854988, compound

Procedure

For example, tetradecafluoropentacene (9) is obtained by reacting 1,2,3,4,5,5,6,6,7,7,8,9,10,11,12,12,13,13,14,14-eicosafluoro-5,6,7,12,13,14-hexahydropentacene (7) with a reducing agent (scheme 15). In addition, 5,6,7,12,13,14-hexafluoropentacene (10) is obtained by reacting 5,5,6,7,7,12,12,13,14,14-decafluoro-5,7,12,14-tetrahydropentacene (8) with a reducing agent (scheme 16).

Sources & evidence

ORD record
ord-10992039aa954bbaadd7639968324824
Source dataset
uspto-grants-2008_10
Patent number
US07439407B2

Reaction notes

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