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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2165196Generated: October 31, 2026

Sodium Iodide → 3-[5-[4-(2-Methoxyphenyl)piperazin-1-yl]pentyl]thieno[3,4-d]-pyrimidine-2,4-dione

https://huagongshe.com/reaction/2165196

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
ReactantSodium HydroxideHCID 14798—
ReactantSodium BicarbonateHCID 516892—
ReactantN-(2-Methoxyphenyl)piperazine hydrochlorideHCID 9899402—
ReactantN-(5-bromopentyl)-N'-(4-carbomethoxythien-3-yl)ureaHCID 15697668—
SolventWaterHCID 962—
SolventIsopropanolHCID 3776—
Product3-[5-[4-(2-Methoxyphenyl)piperazin-1-yl]pentyl]thieno[3,4-d]-pyrimidine-2,4-dioneHCID 15697669109.7%

Reaction Steps

The above urea (8.0 g, 23 mmol) was reacted with 1-(2-methoxyphenyl)piperazine hydrochloride (10.48 g, 45 mmol), NaI (1.72 g, 11 mmol) and NaHCO3 (7.69 g, 92 mmol) in 50 mL of 2-propanol at reflux for 6 hours under a nitrogen blanket. After cooling, water was added and the 2-propanol was removed by distillation. The brown residue was dissolved in CH2Cl2 and washed with water and brine and dried (MgSO4). After the solvent has been removed in vacuo, the tan residue was dissolved in MeOH and treated with 1.1 equivalents of 50% NaOH and the solution was refluxed for 3.5 hours. The pH of the solution was adjusted to 6 with 2N HCL and the methanol was removed by distillation. The resulting oil was dissolved in CH2Cl2 and washed with water and brine and dried (MgSO4). Solvent removal produced 10.81 g (91%) of 3-[5-[4-(2-methoxyphenyl)piperazin-1-yl]pentyl]thieno[3,4-d]pyrimidine-2,4-dione which was crystallized from CH2Cl2 /ether to afford a tan solid, mp 148°-153° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04939137
Source datasetuspto-grants-1990_07
ORD IDord-980c0d2190f046c19db637afbef5c3ef
Source noteuspto-grants-1990_07