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HRID2165818

反应详情

EQUATION

反应方程式

HRID 2165818 的结构方程式

REACTANTS

反应物

2
结构：Cn1cnc2c1c(=O)[nH]c(=O)n2C
HCID5429

Theobromine

C7H8N4O2

结构：Clc1ccc(OCCCCCCBr)cc1
HCID11449208

BENZENE, 1-[(6-BROMOHEXYL)OXY]-4-CHLORO-

C12H16BrClO

PRODUCTS

生成物

1
结构：Cn1cnc2c1c(=O)n(CCCCCCOc1ccc(Cl)cc1)c(=O)n2C
HCID14423764

未命名化合物

收率 61%

PROCEDURE

实验过程

Theobromine and 6-(4-chlorophenoxy)hexyl bromide were reacted and treated in substantially the same manner as described in Example 9(a) to give 6-(4-chlorophenoxy)hexyltheobromine (61%).

WORKUP

后处理

  1. additiontreated in substantially the same manner