HRID2169456

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID86725964

未命名化合物

结构：CN(CCO[Si](C)(C)C(C)(C)C)C(=O)c1nc(CC2(n3ccc4cccnc43)CCCC2)nc(O)c1OCc1ccccc1

HCID178484774

未命名化合物

结构：O=C(O)c1nc(CC2(n3ccc4cccnc43)CCCC2)nc(O)c1OCc1ccccc1

HCID178524881

未命名化合物

PRODUCTS

生成物

结构：CC(C)(C)[Si](C)(C)OCCN(C(=O)c1nc(CC2(n3ccc4cccnc43)CCCC2)nc(O)c1OCc1ccccc1)C1CCC1

HCID178455283

未命名化合物

PROCEDURE

实验过程

5-Benzyloxy-6-hydroxy-2-(1-pyrrolo[2,3-b]pyridin-1-yl-cyclopentylmethyl)-pyrimidine-4-carboxylic acid [2-(tert-butyl-dimethylsilanyloxy)-ethyl]-cyclobutyl-amide (425) was prepared following the same method as described for 5-benzyloxy-6-hydroxy-2-(1-pyrrolo[2,3-b]pyridin-1-yl-cyclopentylmethyl)-pyrimidine-4-carboxylic acid [2-(tert-butyl-dimethylsilanyloxy)-ethyl]-methyl-amide (405) from 5-benzyloxy-6-hydroxy-2-(1-pyrrolo[2,3-b]pyridin-1-yl-cyclopentylmethyl)-pyrimidine-4-carboxylic acid (8f) (140 mg, 0.32 mmol) and [2-(tert-butyl-dimethylsilanyloxy)-ethyl]-cyclobutyl-amine (108 mg, 0.47 mmol) to get a white sticky solid (200 mg, 97%, impure).

WORKUP

后处理

customto get a white sticky solid (200 mg, 97%, impure)

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-68ac0a5f1f444ba68edba7a826b95fe6
来源数据集: uspto-grants-2015_06
DOI: 10.6084/m9.figshare.5104873.v1
专利: US09045486B2
来源说明: uspto-grants-2015_06

反应 SMILES

[Si:1]([O:8][CH2:9][CH2:10][N:11]([CH3:44])[C:12]([C:14]1[C:19]([O:20][CH2:21][C:22]2[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=2)=[C:18]([OH:28])[N:17]=[C:16]([CH2:29][C:30]2([N:35]3[C:39]4=[N:40][CH:41]=[CH:42][CH:43]=[C:38]4[CH:37]=[CH:36]3)[CH2:34][CH2:33][CH2:32][CH2:31]2)[N:15]=1)=[O:13])([C:4]([CH3:7])([CH3:6])[CH3:5])([CH3:3])[CH3:2].[CH2:45](OC1C(C(O)=O)=NC(CC2(N3C4=NC=CC=C4C=C3)CCCC2)=NC=1O)[C:46]1C=CC=C[CH:47]=1.[Si](OCCNC1CCC1)(C(C)(C)C)(C)C>>[Si:1]([O:8][CH2:9][CH2:10][N:11]([CH:44]1[CH2:47][CH2:46][CH2:45]1)[C:12]([C:14]1[C:19]([O:20][CH2:21][C:22]2[CH:27]=[CH:26][CH:25]=[CH:24][CH:23]=2)=[C:18]([OH:28])[N:17]=[C:16]([CH2:29][C:30]2([N:35]3[C:39]4=[N:40][CH:41]=[CH:42][CH:43]=[C:38]4[CH:37]=[CH:36]3)[CH2:31][CH2:32][CH2:33][CH2:34]2)[N:15]=1)=[O:13])([C:4]([CH3:5])([CH3:6])[CH3:7])([CH3:3])[CH3:2]