HRID2172903

反应详情

EQUATION

反应方程式

HRID 2172903 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

Using the general procedure described above, the reaction of 8 (90 mg, 0.23 mmol) and 1 N NaOH provided 65 mg of AAG104 as a transparent solid in 92% yield. TLC Rf 0.34 (chloroform-methanol 15:1); mp 225.2-225.6° C.; 1H NMR (DMSO-d6) δ 3.74 (s, 3H, OCH3), 6.05 (s, 2H, NH2, exch), 6.88-8.07 (m, 8H, Ar—H), 8.16 (s, 1H, 4-NH, exch), 11.20 (s, 1H, 9-NH, exch). Anal. Calculated (C17H15N5O. 0.15 (C2H5)2O): C, 66.79; H, 5.25; N, 22.13. Found: C, 66.77; H, 5.08; N, 22.13.

WORKUP

后处理

  1. customprovided 65 mg of AAG104 as a transparent solid in 92% yield