HRID2176013

反应详情

EQUATION

反应方程式

HRID 2176013 的结构方程式

PROCEDURE

实验过程

By using 200 mg of methyl 4-[2-(4-{[(2-{[3-({[2-(methylamino)ethyl](pentan-3-yl)amino}methyl)benzoyl]amino}-4,5,6,7-tetrahydro-1-benzothiophen-3-yl)carbonyl]amino}phenyl)ethyl]benzoate and 79 mg of methyl 3-(bromomethyl)benzoate, the reaction similar to Preparation Example 30 was performed, thereby obtaining 220 mg of methyl 3-{[(2-{[3-({3-[(4-{2-[4-(methoxycarbonyl)phenyl]ethyl}phenyl)carbamoyl]-4,5,6,7-tetrahydro-1-benzothiophen-2-yl}carbamoyl)benzyl](pentan-3-yl)amino}ethyl)(methyl)amino]methyl}benzoate.

WORKUP

后处理

  1. customthe reaction
  2. customsimilar to Preparation Example 30