反应详情

Example 19 was prepared in an analogous way as Example 11 substituting Intermediate 3 for Intermediate 1 and Intermediate 13 for Intermediate 12 in Step A. 1H NMR (500 MH, CDCl3) δ 8.53 (dd, J=12.7, 11.7 Hz, 1H), 8.03-7.99 (m, 1H), 7.92-7.80 (m, 1H), 7.70-7.60 (m, 2H), 7.40-7.27 (m, 3H), 5.78 (s, 1H), 5.10-4.56 (m, 1H), 3.75-3.31 (m, 1H), 3.31-2.76 (m, 2H), 1.83-1.38 (m, 3H). MS (ESI): mass calculated for C20H16F4N4O, 404.13. m/z found 405.2 [M+H]+.