HRID2180025

反应详情

EQUATION

反应方程式

HRID 2180025 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

Compound 14 was subjected to general procedure J. Yield=81%. TLC: Rf=0.50 (10% EtOAc/Hexane). 1H NMR (400 MHz, CDCl3): δ0.05 (s, 6H), 0.90 (s, 9H), 2.20 (m, 1H), 2.30 (m, 1H), 5.10 (s, 1H), 6.05 (m, 2H), 6.10 (m, 1H), 8.20 (d, 2H), 8.20 (d, 2H). Subsequent subjection of the product to general procedure E gave compound 22. Yield=85%. TLC: Rf=0.33 (25% EtOAc/Hexane). 1H NMR (400 MHz, CDCl3): δ0.05 (s, 6H), 0.90 (s, 9H), 2.05 (m, 2H), 5.00 (m, 1H), 5.05 (m, 1H), 5.95 (m, 2H).