HRID2180122

反应详情

EQUATION

反应方程式

HRID 2180122 的结构方程式

PROCEDURE

实验过程

Using an analogous procedure to that described in Example 1, 4-chloro-6-methoxy-7-(2-(2-methoxyethoxy)ethoxy)cinnoline (100 mg, 0.32 mmol) was reacted with 4-fluoro-5-hydroxy-2-methylindole (64 mg, 0.38 mmol), (prepared as described for the starting material in Example 1), to give 4-(4-fluoro-2-methylindol-5-yloxy)-6-methoxy-7-(2-(2-methoxyethoxy)ethoxy)cinnoline (26 mg, 19%).

WORKUP

后处理

  1. custom(prepared