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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2182019Generated: October 26, 2026

1,5-Pentanediol → PhCH2OCH2CH(CH3)O(CH2)5OH

https://huagongshe.com/reaction/2182019

Reaction equation

Participants

RoleNameHCIDCharge
Reactant1,5-PentanediolHCID 8105—
ReactantPotassium HydroxideHCID 14797—
Reactant1,4-DioxaneHCID 31275—
ReactantToluene-4-sulfonic acid, 2-benzyloxy-1-methylethyl esterHCID 562182—
SolventWaterHCID 962—
ProductPhCH2OCH2CH(CH3)O(CH2)5OHHCID 8580296237.1%

Reaction Conditions

Temperature80 °C

Reaction Steps

Into another flask, KOH (25.8 g), HO(CH2)5OH (47.9 g) and dioxane (200 ml) were charged and stirred at 90° C. until KOH was dissolved. Then, from a dropping funnel, PhCH2OCH2CH(CH3)OTs (71.2 g) and dioxane (75 ml) were added at 90° C. over a period of 20 minutes. After further stirring at 80° C. for 20 hours, water (350 ml) was added. Extraction with dichloromethane (100 ml) was carried out three times, and the extracted organic phase was washed with water (150 ml), then dried over anhydrous magnesium sulfate, filtered and further concentrated. The concentrated liquid was purified by silica gel column (eluent: hexane/ethyl acetate) to obtain PhCH2OCH2CH(CH3)O(CH2)5OH(20.8 g).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06894187B2
Source datasetuspto-grants-2005_05
ORD IDord-06eee858ce4e43eb8fadd7a6a83214fa
Source noteuspto-grants-2005_05