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HRID2191019

反应详情

EQUATION

反应方程式

HRID 2191019 的结构方程式

REACTANTS

反应物

2
结构：CCOP(=O)(C=CC1CC(OC(=O)c2ccccc2)C(n2cnc3c(N)ncnc32)O1)OCC
HCID72247311

未命名化合物

结构：Nc1nc2c(nnn2C2OC(C=CP(=O)(O)O)CC2O)c(=O)[nH]1
HCID136381448

未命名化合物

PRODUCTS

生成物

1
结构：Nc1ncnc2c1ncn2C1OC(C=CP(=O)(O)O)CC1O
HCID68593528

未命名化合物

收率 76.8%

PROCEDURE

实验过程

Compound 12.2 (103 mg, 68% yield) was synthesized from compound 12.1 (200 mg, 0.41 mmol) using the procedure for the preparation of compound 10.2. 1H NMR (D2O) δ 2.10 (m, 1H), 2.19 (m, 1H), 4.62 (m, 1H), 4.87 (m, 1H), 5.95 (m, 2H), 6.16 (m, 1H), 8.03 (s, 1H), 8.09 (s, 1H). 31P NMR (D2O) d 10.07. LRMS (ESI) MH+ C11H14N5O5P requires 328.2. Found 328.0.