HRID219450

反应详情

EQUATION

反应方程式

HRID 219450 的结构方程式

PROCEDURE

实验过程

Example 4e (100 mg, 0.28 mmol) was reacted with 2-pyridin-2-ylethyl methanesulfonate (1.6 eq.) as described under General Procedure F to give the title compound (56 mg, 43%). 1H NMR (300 MHz, CDCl3) δ 8.51 (d, J=4.2 Hz, 1H), 7.57 (dt, J=7.7, 1.8 Hz, 1H), 7.19-7.09 (m, 4H), 6.96-6.91 (m, 2H), 4.34 (t, J=6.6 Hz, 2H), 3.83 (t, J=6.6 Hz, 2H), 3.73 (s, 3H), 3.11 (6.6 Hz, 2H), 2.99-2.92 (m, 1H), 2.26 (s, 3H), 2.07 (s, 3H), 2.00 (s, 3H), 1.95-1.88 (m, 2H), 1.25 (d, J=7.0 Hz, 3H).