Lithium Hydroxide → 2-(1-(Methylsulphonyl)indolin-5-yl)propanoic acid

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Reaction Steps

the propanoate (1.78 mmol, 0.53 g) obtained in step b was dissolved in a THF-water mixture (5 ml, 2:1), LiOH (5.34 mmol, 0.128 g) was added and refluxing was carried out for 12 h. The reaction mixture was extracted with diethyl ether (25 ml), the aqueous phase was acidified to pH 2 with 1 N HCl and extraction was carried out with EE (3×25 ml). The combined organic phases were dried over magnesium sulphate and the solvent was removed in a vacuum. It was possible to obtain 2-(1-(methylsulphonyl)indolin-5-yl)propanoic acid in an 80% yield (0.382 g).

Provenance & Evidence