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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 219539Generated: October 29, 2026

Sodium Methoxide → (2R,3S,5R)-2-(hydroxymethyl)-5-[2,5,6-trichloro-3-(2-furyl)indol-1-yl]tetrahydrofuran-3-ol

https://huagongshe.com/reaction/219539

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium MethoxideHCID 10942334—
ReactantChloroform methanolHCID 21584188—
Reactant2,5,6-Trichloro-3-(2-furyl)-1-(3,5-di-O-toluoyl-2-deoxy-beta-D-ribofuranosyl)indoleHCID 67099050—
SolventMethanolHCID 887—
SolventChloroformHCID 6212—
Product(2R,3S,5R)-2-(hydroxymethyl)-5-[2,5,6-trichloro-3-(2-furyl)indol-1-yl]tetrahydrofuran-3-olHCID 527300675.6%

Reaction Steps

2,5,6-Trichloro-3-(2-furyl)-1-(3,5-di-O-toluoyl-2-deoxy-β-D-ribofuranosyl)indole (4.76, 142 mg, 0.22 mmol) was suspended in dry MeOH (10 mL) to which was added sodium methoxide (30 mg, 0.56 mmol). The suspension was stirred at room temperature for 45 min, until the solids were completely dissolved. The solvent was then removed under vacuum, and the residue suspended in brine (50 mL). The aqueous suspension was extracted with EtOAc (2×50 mL), and the combined organic extracts were dried over MgSO4, filtered and evaporated to yield a clear oil. The oil was dissolved in CHCl3 (1 mL) and subjected to column chromatography (40×350 mm) on silica gel with 10% MeOH/CHCl3. Fractions containing product were pooled and evaporated to yield a pale yellow solid which was recrystallized from 10% MeOH/CHCl3 and hexane to yield 67 mg (75%) of 4.78 as a white crystalline solid: mp 140-141 C; Rf 0.5 (10% MeOH/CHCl3); 1H-NMR (500 MHz, DMSO-d6): δ 8.46 (s, 1H), 8.14 (s, 1H), 7.86 (s, 1H), 6.88 (d, 1H), 6.68 (s, 1H), 6.47 (dd, 1H), 5.42 (d, 1H, D2O exch.), 5.23 (s, 1H, D2O exch.), 4.45 (d, 1H), 3.89 (d, 1H), 3.73 (s, 2H), 2.55 (m, 1H), 2.13 (m, 1H). 13C-NMR (125 MHz, DMSO-d6): δ 146.54, 142.25, 132.30, 125.61, 124.39, 124.09, 122.64, 120.75, 114.98, 111.51, 106.91, 104.87, 87.25, 85.04, 69.98, 60.91, 38.97. HRMS (EI) m/z calcd. for C17H14Cl3NO4 400.9988. found 400.9986. Anal calcd for C17H14Cl3NO4.¼H2O: C, 50.15; H, 3.59; N, 3.44. Found: C, 50.17; H, 3.65; N, 3.43.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08202844B2
Source datasetuspto-grants-2012_06
ORD IDord-01f0943a92554048b08a8f7d44e3f1f5
Source noteuspto-grants-2012_06