HRID2196511

反应详情

EQUATION

反应方程式

HRID 2196511 的结构方程式

PROCEDURE

实验过程

Following the same procedure as described for compound 14 (step 4, scheme 2, example 1c) except using 21 (278 mg, 1.58 mmol) instead of 13 to afford 22 (182 mg, 37%) as a beige solid. LRMS (ESI): calc. 309.1; found 310.1 (MH)+.