HRID2197915

反应详情

EQUATION

反应方程式

HRID 2197915 的结构方程式

PROCEDURE

实验过程

The product from Example 171a (0.56 g, 1.9 mmol) was reacted with SnCl2 following the procedure described in Example 1f to give the title compound (0.60 g, 83%).