Sodium Fluoride → 10163-15-2
Reaction equation
[P:1]([F:5])([O-:4])([O-:3])=[O:2].[Na+:6].[Na+].[F-:8].[Na+]>>[F:8][F:5].[P:1]([F:5])([O-:4])([O-:3])=[O:2].[Na+:6].[Na+:6]Participants
4
Procedure
Sodium monofluorophosphate is used in amount to provide about 700-1090 ppm fluorine to the dental cream in which the total amount of fluorine is about 1000-1670, with about 30-35% by weight to the total fluorine being provided by sodium fluoride (about 300-580 ppm). This corresponds to about 0.5-1.2% by weight of sodium monofluorophosphate and about 0.06-0.11% by weight of sodium fluoride. Preferably, the dental cream contains about 1000-1500 ppm, most preferably, about 950-1000 ppm fluorine provided by sodium monofluorophosphate and about 450-500 ppm provided by sodium fluoride.
Sources & evidence
- ORD record
- ord-ba4a99040cb4438494f25c490ef377eb
- Source dataset
- uspto-grants-1982_11
- Patent number
- US04357317
Reaction notes
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