HRID2198603

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID6451240

未命名化合物

结构：CS(=O)(=O)Oc1ccc(-c2cc3ccc(OS(C)(=O)=O)cc3s2)cc1

HCID13286041

4-{6-[(Methanesulfonyl)oxy]-1-benzothiophen-2-yl}phenyl methanesulfonate

C16H14O6S3

HCID66625687

未命名化合物

PRODUCTS

生成物

结构：CC(C)N(CCOc1ccc(C(=O)c2c(-c3ccc(OS(C)(=O)=O)cc3)sc3cc(OS(C)(=O)=O)ccc23)cc1)C(C)C.Cl

HCID131712868

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID702

Ethanol

C2H6O

PROCEDURE

实验过程

A 7.6 g. portion of 4-(2-diisopropylaminoethoxy)benzoic acid, hydrochloride, was converted to the acid chloride as described in Example 1 above, and was used to acylate 5 g. of 6-methanesulfonyloxy-2-(4-methanesulfonyloxyphenyl)benzo[b]thiophene in the presence of 20 g. of aluminum chloride. Work up according to Example 4 gave 7.4 g. of crystalline product after trituration of the isolated oil with denatured ethanol. The product was recrystallized from denatured ethanol to obtain 6.5 g. of purified product, and a 1.5 g. portion was further purified by chromatography over silica gel, eluting with 1:3 methanol:chloroform to obtain 1.15 g. of analytical sample, m.p. 198°-201°.

WORKUP

后处理

customgave 7.4 g
customThe product was recrystallized from denatured ethanol
customto obtain 6.5 g
customportion was further purified by chromatography over silica gel
washeluting with 1:3 methanol
customchloroform to obtain 1.15 g

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-881a8cf9edce4a779dcd1d31678b510d
来源数据集: uspto-grants-1982_11
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04358593
来源说明: uspto-grants-1982_11

反应 SMILES

[ClH:1].[CH:2]([N:5]([CH:18]([CH3:20])[CH3:19])[CH2:6][CH2:7][O:8][C:9]1[CH:17]=[CH:16][C:12]([C:13]([OH:15])=O)=[CH:11][CH:10]=1)([CH3:4])[CH3:3].[CH3:21][S:22]([O:25][C:26]1[CH:27]=[CH:28][C:29]2[CH:33]=[C:32]([C:34]3[CH:39]=[CH:38][C:37]([O:40][S:41]([CH3:44])(=[O:43])=[O:42])=[CH:36][CH:35]=3)[S:31][C:30]=2[CH:45]=1)(=[O:24])=[O:23].[Cl-].[Al+3].[Cl-].[Cl-]>C(O)C>[ClH:1].[CH:18]([N:5]([CH:2]([CH3:3])[CH3:4])[CH2:6][CH2:7][O:8][C:9]1[CH:10]=[CH:11][C:12]([C:13]([C:33]2[C:29]3[CH:28]=[CH:27][C:26]([O:25][S:22]([CH3:21])(=[O:24])=[O:23])=[CH:45][C:30]=3[S:31][C:32]=2[C:34]2[CH:35]=[CH:36][C:37]([O:40][S:41]([CH3:44])(=[O:42])=[O:43])=[CH:38][CH:39]=2)=[O:15])=[CH:16][CH:17]=1)([CH3:20])[CH3:19]