HRID22076

反应详情

EQUATION

反应方程式

HRID 22076 的结构方程式

PROCEDURE

实验过程

Epoxy alcohol 10, 1.2 eq of TESOTf, and 1.5 eq of collidine were reacted as in the preparation of 16 give 80% of aldehyde 11. 1H NMR (CDCl3, 500.35 MHz) δ:9.64 (1H, d J=0.77 Hz), 7.30-7.05 (5H,m) 4.37 (1H, J=3.06, 10.40 Hz), 2.76 (1H, d J=6.64 Hz), 2.75 (2H, d J=7.42 Hz), 2.27 (1H, qdd, J=7.00, 3.38, 0.77 Hz), 1.10 (3H, d, J=7.04 Hz), 0.95-0.75 (6H, m), 0.6-0.4 (9H, m). 1H NMR integration of δ 9.64 to the contaminant δ 9.71 indicated a 93.6:6.4 ratio.