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HRID220967

反应详情

EQUATION

反应方程式

HRID 220967 的结构方程式

REACTANTS

反应物

4
结构：O=C1CCCNc2ccccc21
HCID294788

1,2,3,4-Tetrahydro-5H-1-benzazepin-5-one

C10H11NO

结构：C1COCCO1.Cl
HCID20443148

1,4-Dioxane hydrochloride

C4H9ClO2

结构：Cc1cc2nc3c(=O)[nH]c(=O)nc-3n(C[C@H](O)[C@H](O)[C@H](O)COP(=O)([O-])O)c2cc1C.[Na+]
HCID23666409

Riboflavin 5'-(dihydrogen phosphate), sodium salt (1:1)

C17H20N4NaO9P

结构：Cn1ncc2c1Nc1cc(Cl)ccc1N(C(=O)c1ccc(CNC(=O)OC(C)(C)C)c(Cl)c1)C2
HCID136128408

未命名化合物

PRODUCTS

生成物

1
结构：Cl.Cn1ncc2c1Nc1cc(Cl)ccc1N(C(=O)c1ccc(CN)c(Cl)c1)C2
HCID136346649

未命名化合物

收率 100%

PROCEDURE

实验过程

[2-Chloro-4-(6-chloro-3-methyl-4,10-dihydro-3H-2,3,4,9-tetraaza-benzo[f]azulene-9-carbonyl)-benzyl]-carbamic acid tert-butyl ester from Example E106.1 (570 mg, 1.13 mmol) was reacted with 4N HCl/dioxan using an analogous procedure to that described for Example E4.2 to yield the title compound (490 mg, 100%).