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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 2209863Generated: October 26, 2026

Bromine → Perfluorooctyl bromide

https://huagongshe.com/reaction/2209863

Reaction equation

Participants

RoleNameHCIDCharge
ReactantBromineHCID 24408—
ReactantFluorineHCID 24524—
ReactantPerfluorononanoic acidHCID 67821—
ProductPerfluorooctyl bromideHCID 9873142.9%

Reaction Steps

Perfluorononanoic acid 100 g (0.215 mole), bromine 21.0 g (0.129 mole) and Freon 113 (500 ml) were mixed in the plastic reactor. The mixture was treated with fluorine in the same manner as described in Example 1. Approximately 1.7 fold excess fluorine was used, producing 92 grams of perfluorooctyl bromide (86% yield). Thus, using approximately half the amount of bromine as used in Example 1 produced a lower yield of the perfluoroalkyl halide.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05455373
Source datasetuspto-grants-1995_10
ORD IDord-a8f75fceb2184feea80b206f32a1ed69
Source noteuspto-grants-1995_10