HRID221322

反应详情

EQUATION

反应方程式

HRID 221322 的结构方程式

REACTANTS

反应物

2

结构：Cc1cccc2nc(C(C)Nc3ncnc4c3ncn4COCC[Si](C)(C)C)n(-c3cccc(C#N)c3)c(=O)c12

未命名化合物

结构：Cc1cccc2nc(C(C)Nc3ncnc4[nH]cnc34)n(-c3cccc(O)c3)c(=O)c12

未命名化合物

PRODUCTS

生成物

1

结构：Cc1cccc2nc(C(C)Nc3ncnc4[nH]cnc34)n(-c3cccc(C#N)c3)c(=O)c12

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1

结构：CO

Methanol

CH4O

PROCEDURE

实验过程

Compound 141 was treated with 4N HCL in MeOH for 1 hour using the procedure described for compound 121 (step B) to provide compound 140. m/z=423 (M+H). The structure of compound 140 is shown below.