HRID221324

反应详情

EQUATION

反应方程式

HRID 221324 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

Compound 143 was treated with 4N HCL in MeOH for 1.5 hours using the procedure described for compound 121 (step D) to provide compound 142. m/z=441 (M+H). The structure of compound 142 is shown below.